题目
LeetCode 2482.行和列中一和零的差值
解释
## 题目描述
给你一个下标从 0 开始的 m x n 二进制矩阵 grid 。
我们按照如下过程,定义一个下标从 0 开始的 m x n 差值矩阵 diff :
令第 i 行一的数目为 onesRowi 。
令第 j 列一的数目为 onesColj 。
令第 i 行零的数目为 zerosRowi 。
令第 j 列零的数目为 zerosColj 。
diff[i][j] = onesRowi + onesColj - zerosRowi - zerosColj
请你返回差值矩阵 diff 。
## 示例
**示例 1:**
**输入:** grid = [[0,1,1],[1,0,1],[0,0,1]]
**输出:** [[0,0,4],[0,0,4],[-2,-2,2]]
**解释:** - diff[0][0] = onesRow0 + onesCol0 - zerosRow0 - zerosCol0 = 2 + 1 - 1 - 2 = 0
- diff[0][1] = onesRow0 + onesCol1 - zerosRow0 - zerosCol1 = 2 + 1 - 1 - 2 = 0
- diff[0][2] = onesRow0 + onesCol2 - zerosRow0 - zerosCol2 = 2 + 3 - 1 - 0 = 4
- diff[1][0] = onesRow1 + onesCol0 - zerosRow1 - zerosCol0 = 2 + 1 - 1 - 2 = 0
- diff[1][1] = onesRow1 + onesCol1 - zerosRow1 - zerosCol1 = 2 + 1 - 1 - 2 = 0
- diff[1][2] = onesRow1 + onesCol2 - zerosRow1 - zerosCol2 = 2 + 3 - 1 - 0 = 4
- diff[2][0] = onesRow2 + onesCol0 - zerosRow2 - zerosCol0 = 1 + 1 - 2 - 2 = -2
- diff[2][1] = onesRow2 + onesCol1 - zerosRow2 - zerosCol1 = 1 + 1 - 2 - 2 = -2
- diff[2][2] = onesRow2 + onesCol2 - zerosRow2 - zerosCol2 = 1 + 3 - 2 - 0 = 2
**示例 2:**
**输入:** grid = [[1,1,1],[1,1,1]]
**输出:** [[5,5,5],[5,5,5]]
**解释:** - diff[0][0] = onesRow0 + onesCol0 - zerosRow0 - zerosCol0 = 3 + 2 - 0 - 0 = 5
- diff[0][1] = onesRow0 + onesCol1 - zerosRow0 - zerosCol1 = 3 + 2 - 0 - 0 = 5
- diff[0][2] = onesRow0 + onesCol2 - zerosRow0 - zerosCol2 = 3 + 2 - 0 - 0 = 5
- diff[1][0] = onesRow1 + onesCol0 - zerosRow1 - zerosCol0 = 3 + 2 - 0 - 0 = 5
- diff[1][1] = onesRow1 + onesCol1 - zerosRow1 - zerosCol1 = 3 + 2 - 0 - 0 = 5
- diff[1][2] = onesRow1 + onesCol2 - zerosRow1 - zerosCol2 = 3 + 2 - 0 - 0 = 5
## 约束条件
m == grid.length
n == grid[i].length
1 <= m, n <= 105
1 <= m * n <= 105
grid[i][j] 要么是 0 ,要么是 1 。
## LeetCode 链接
https://leetcode.cn/problems/difference-between-ones-and-zeros-in-row-and-column/
答案
正在疯狂整理答案中......
